A 0.250 L volume of water displaced when an object is submerged exerts a buoyant force equal to ρ g V. If ρ water = 1000 kg/m³, V = 0.00025 m³, what is the buoyant force approximately?

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Multiple Choice

A 0.250 L volume of water displaced when an object is submerged exerts a buoyant force equal to ρ g V. If ρ water = 1000 kg/m³, V = 0.00025 m³, what is the buoyant force approximately?

Buoyant force equals the weight of the fluid displaced. Use F_b = ρ g V. With ρ = 1000 kg/m^3 and V = 0.00025 m^3, ρV = 1000 × 0.00025 = 0.25 kg. Multiply by g ≈ 9.8 m/s^2: F_b ≈ 0.25 × 9.8 = 2.45 N. So the buoyant force is about 2.45 newtons.

Buoyant force equals the weight of the fluid displaced. Use F_b = ρ g V. With ρ = 1000 kg/m^3 and V = 0.00025 m^3, ρV = 1000 × 0.00025 = 0.25 kg. Multiply by g ≈ 9.8 m/s^2: F_b ≈ 0.25 × 9.8 = 2.45 N. So the buoyant force is about 2.45 newtons.

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