A 1.00 mol sample of an ideal gas at 1.00 atm and 25°C occupies what volume? Use R = 0.0821 L·atm/mol·K.

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the Dual Enrollment Physical Science Midterm. Study with flashcards and multiple choice questions, each with hints and explanations. Ace your exam!

Multiple Choice

A 1.00 mol sample of an ideal gas at 1.00 atm and 25°C occupies what volume? Use R = 0.0821 L·atm/mol·K.

Explanation:
PV = nRT is the relationship to use here. With one mole of gas at 1.00 atm and 25°C (which is 298 K), the volume is V = nRT/P = (1.00 mol)(0.0821 L·atm/mol·K)(298 K) / (1.00 atm) ≈ 24.47 L. So the gas at these conditions would occupy about 24.47 liters.

PV = nRT is the relationship to use here. With one mole of gas at 1.00 atm and 25°C (which is 298 K), the volume is V = nRT/P = (1.00 mol)(0.0821 L·atm/mol·K)(298 K) / (1.00 atm) ≈ 24.47 L. So the gas at these conditions would occupy about 24.47 liters.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy