A thin lens with f = 10 cm forms an image when do = 15 cm. What is the magnification m of the image?

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Prepare for the Dual Enrollment Physical Science Midterm. Study with flashcards and multiple choice questions, each with hints and explanations. Ace your exam!

Multiple Choice

A thin lens with f = 10 cm forms an image when do = 15 cm. What is the magnification m of the image?

Explanation:
For a thin lens, the image magnification is m = - di / do, and the distances follow 1/f = 1/do + 1/di. With f = 10 cm and do = 15 cm, solve for di: 1/di = 1/f - 1/do = 1/10 - 1/15 = 1/30, so di = 30 cm. Then m = - di / do = -30 / 15 = -2. The negative sign means the image is inverted, and the magnitude 2 means it is twice as large as the object. Therefore, the magnification is -2.

For a thin lens, the image magnification is m = - di / do, and the distances follow 1/f = 1/do + 1/di. With f = 10 cm and do = 15 cm, solve for di: 1/di = 1/f - 1/do = 1/10 - 1/15 = 1/30, so di = 30 cm. Then m = - di / do = -30 / 15 = -2. The negative sign means the image is inverted, and the magnitude 2 means it is twice as large as the object. Therefore, the magnification is -2.

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