How long would light take to travel 1.20 × 10^6 meters, given the speed of light as 3.00 × 10^8 meters per second?

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Prepare for the Dual Enrollment Physical Science Midterm. Study with flashcards and multiple choice questions, each with hints and explanations. Ace your exam!

Multiple Choice

How long would light take to travel 1.20 × 10^6 meters, given the speed of light as 3.00 × 10^8 meters per second?

Explanation:
Time is found by dividing distance by speed. With a distance of 1.20 × 10^6 meters and the speed of light as 3.00 × 10^8 meters per second, you get time = (1.20 × 10^6) / (3.00 × 10^8) seconds. That simplifies to (1.20/3.00) × 10^(6−8) = 0.40 × 10^−2 = 4.0 × 10^−3 s, which is 0.004 seconds. So light would take 0.004 seconds to travel that distance.

Time is found by dividing distance by speed. With a distance of 1.20 × 10^6 meters and the speed of light as 3.00 × 10^8 meters per second, you get time = (1.20 × 10^6) / (3.00 × 10^8) seconds. That simplifies to (1.20/3.00) × 10^(6−8) = 0.40 × 10^−2 = 4.0 × 10^−3 s, which is 0.004 seconds. So light would take 0.004 seconds to travel that distance.

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