If a 2 kg object experiences a force of 6 N for 0.5 s starting from rest, what is its final velocity?

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Multiple Choice

If a 2 kg object experiences a force of 6 N for 0.5 s starting from rest, what is its final velocity?

A constant force on a mass produces a constant acceleration, given by a = F/m. With F = 6 N and m = 2 kg, the acceleration is 3 m/s^2. Starting from rest, the velocity after 0.5 seconds is v = v0 + a t = 0 + (3 m/s^2)(0.5 s) = 1.5 m/s. You can also see this via impulse: Δv = (F Δt)/m = (6 × 0.5)/2 = 1.5 m/s.

A constant force on a mass produces a constant acceleration, given by a = F/m. With F = 6 N and m = 2 kg, the acceleration is 3 m/s^2. Starting from rest, the velocity after 0.5 seconds is v = v0 + a t = 0 + (3 m/s^2)(0.5 s) = 1.5 m/s. You can also see this via impulse: Δv = (F Δt)/m = (6 × 0.5)/2 = 1.5 m/s.

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